Unimolecular Elimination
The carbocation produced when the leaving group departs can evolve in an alternative way to the SN1 reaction: elimination of a proton from the adjacent position.
The nucleophile, ACTING AS A BASE, can remove a proton from the carbon adjacent to the carbocation, leading to an olefin.
In the case of the methanolysis of tert-butyl chloride, it is the methanol that acts as a base, taking the proton and producing isobutylene.
Therefore, once formed, the carbocation can evolve by two different pathways. The qualitative energy diagram is as follows:
The substitution-to-elimination ratio does not depend on the leaving group because the carbocation is a common intermediate in both pathways, but it does depend on the basicity/nucleophilicity relationship of the attacking base/nucleophile.
Any hydrogen on a carbon adjacent to the one bearing the leaving group can participate in the E1 reaction. Consequently, the carbocation generated from 2-bromooctane can lead to either 1- or 2-octene:
We have now explained why our 'experiment' led to the formation of 20% olefins.
We only have to understand why only traces of 1-octene are produced and why trans-2-octene is the major olefin. These facts will be explained in the chapter on alkenes.