SolutionsFunctional Groups
1. Recognize the functional groups
Each colour marks a functional group:
- carboxylic acid
- ester
- aromatic ring
- phenol
- amide
- aldehyde
- ether
- alcohol
- amine
- alkene
carboxylic acid, ester and aromatic ring
phenol, amide and aromatic ring
aldehyde, ether, phenol and aromatic ring
alcohol, amine, phenol and aromatic ring
carboxylic acid and aromatic ring
alkene, alcohol
2. Classify
a) State whether each alcohol is primary, secondary or tertiary:
- CH3CH2OH — Primary: the carbon bearing the OH is bonded to only one carbon.
- (CH3)2CHOH — Secondary: the carbon bearing the OH is bonded to two carbons.
- (CH3)3COH — Tertiary: the carbon bearing the OH is bonded to three carbons.
b) State whether each amine is primary, secondary or tertiary:
- CH3CH2NH2 — Primary: the nitrogen is bonded to only one carbon.
- CH3CH2NHCH3 — Secondary: the nitrogen is bonded to two carbons.
- CH3CH2N(CH3)2 — Tertiary: the nitrogen is bonded to three carbons.
Note that for alcohols we count the carbons bonded to the carbon bearing the OH, whereas for amines we count the carbons bonded directly to the nitrogen.
c) Which functional group does each compound in these closely related pairs have?
- Acetic acid: carboxylic acid (–COOH) / methyl acetate: ester (–COO–). The ester lacks the acidic H of the OH.
- Propanal: aldehyde (the C=O is at the end of the chain and bears an H) / propanone: ketone (the C=O is between two carbons).
- Ethanamide: amide (the N is bonded to a C=O) / ethanamine: amine (the N is bonded to an sp3 carbon).
3. Which is the main function?
- HOCH2CH2COOH — 3-Hydroxypropanoic acid. The carboxylic acid takes precedence over the alcohol: it gives the suffix “-oic acid” and the OH is named as “hydroxy-”.
- CH3COCH2CH2NH2 — 4-Aminobutan-2-one. The ketone takes precedence over the amine: suffix “-one”; the NH2 is named as “amino-”.
- HOCH2CH2CHO — 3-Hydroxypropanal. The aldehyde takes precedence over the alcohol: suffix “-al”; prefix “hydroxy-”.
- H2NCH2COOH — 2-Aminoethanoic acid (glycine). The acid takes precedence over the amine: suffix “-oic acid”; prefix “amino-”. It is the simplest amino acid.
4. From name to structure and back
a) Write the formula of these compounds:
- ethyl ethanoate (ethyl acetate): CH3COOCH2CH3
- N-methylethanamide: CH3CONHCH3
- but-3-en-2-ol: CH2=CHCH(OH)CH3
- 4-hydroxybenzaldehyde: OHC–C6H4–OH (with the OH in position 4, para to the CHO)
b) Name these compounds:
- CH3CH2CH2COOCH3 — Methyl butanoate (ester)
- CH3CH2OCH2CH3 — Ethoxyethane or diethyl ether (ether)
- (CH3)2CHCOOH — 2-Methylpropanoic acid (carboxylic acid)
- CH3CH2CH(NH2)CH3 — Butan-2-amine (primary amine)
5. Same formula, different function
- C2H6O
- Ethanol, CH3CH2OH (alcohol), and dimethyl ether, CH3OCH3 (ether).
- C3H6O
- Propanal, CH3CH2CHO (aldehyde); propanone, CH3COCH3 (ketone); prop-2-en-1-ol, CH2=CHCH2OH (alcohol and alkene); methoxyethene, CH2=CHOCH3 (ether and alkene); cyclopropanol (alcohol), and cyclic ethers such as oxetane or methyloxirane.
- C3H6O2
- Propanoic acid, CH3CH2COOH (acid); methyl ethanoate, CH3COOCH3, and ethyl methanoate, HCOOCH2CH3 (esters); 1-hydroxypropan-2-one, CH3COCH2OH (ketone and alcohol); 2-hydroxypropanal and 3-hydroxypropanal (aldehyde and alcohol), among others.
They are all functional isomers: same molecular formula, different functional group. You will study this in more detail in Isomerism.
6. Everyday chemistry
| Product | Compound | Functional group |
|---|---|---|
| Vinegar | acetic acid, CH3COOH | carboxylic acid |
| Banana flavour | 3-methylbutyl acetate (isoamyl acetate), CH3COOCH2CH2CH(CH3)2 | ester |
| Fishy smell | trimethylamine, (CH3)3N | amine |
| Nail polish remover | acetone, CH3COCH3 | ketone |
| Alcoholic drinks | ethanol, CH3CH2OH | alcohol |
| Bitter almond aroma | benzaldehyde, C6H5CHO | aldehyde |