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Bimolecular Nucleophilic Substitution

In the reaction of (R)-2-bromooctane with hydroxide, the formation of the major product, (S)-2-octanol, can be easily explained with the aid of the following scheme:

Hydroxide attacks 2-bromooctane from the side opposite the bromide and 2-octanol is formed with inverted configuration

The nucleophile (HO−) has attacked the carbon bearing the halogen (LEAVING GROUP) from the side opposite to the one the latter leaves from. This is the only way to explain the inversion of configuration observed.

The reaction can be performed with other nucleophiles on different substrates with other LEAVING GROUPS:

Examples of SN2 reactions with different substrates, nucleophiles and leaving groups

Mechanistic Aspects