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SolutionsPhysical and Bond Properties

1. Heats of formation

Calculate the heats of formation of butane, cis- and trans-2-butene and 2-butyne from their heats of combustion (kcal/mol): −687.4, −647.7, −646.9 and −615.8, respectively. What conclusions can you draw?

Click here to recall how the calculation is done.

Calculation of the heats of formation: butane −30.6; cis-2-butene −2.7; trans-2-butene −3.5 and 2-butyne +34.4 kcal/mol

Butane is much more stable than its elements; the butenes only slightly (the trans isomer somewhat more than the cis), and 2-butyne is much less stable than its elements.

In the scheme, −57.8 kcal/mol is the enthalpy of formation of gaseous water and −10.52 kcal/mol that of its condensation: together they give that of liquid water (−68.3 kcal/mol), which is the one that corresponds to the heats of combustion given.

2. Acidity

Order from most to least acidic: ethane, ethene, ethyne, ammonia and water. Which base would you use to deprotonate propyne completely?

Water (pKa 15.7) > ethyne (25) > ammonia (34) > ethene (44) > ethane (50). A base whose conjugate acid is weaker than propyne is needed, such as sodium amide (NaNH2) or butyllithium; hydroxide is not enough.

3. Synthesis with alkynides

Propose a synthesis of pent-2-yn-1-ol, CH3CH2C≡CCH2OH, from 1-butyne.

1) NaNH2 (or BuLi); 2) formaldehyde, HCHO; 3) H3O+. The alkynide adds to the carbonyl to give the alkoxide, which on hydrolysis gives the propargylic alcohol.

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